NATIONAL SCIENCE AND MATHS QUIZ PAST QUESTIONS-1

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NATIONAL SCIENCE AND MATHS QUIZ PAST QUESTIONS-1


Find the slope m of the tangent to the given curve at the given point on the curve.

1. y = 3x2 – 5x + 2 at x = 1

ANSWER: m = 1

[dy/dx = 6x – 5, at x = 1, m = 6 – 5 = 1]

2.  y = x3 – x2 – 3x at x = 2

ANSWER: m = 5

[dy/dx = 3x2 – 2x – 3, at x = 2, m = 3(4) – 2(2) – 3 = 12 – 7 = 5]

3. y = x4 – 3x2 + 2x  at x = 1

ANSWER: m = 0

[dy/dx = 4x3 – 6x + 2, at x = 1, m = 4 – 6 + 2 = 0]


Solve for x in the interval 0 < x < π/2. Give answer in radians.

1. sinx = √3/2

ANSWER: x = π/3 radians

2. cosx = √3/2

ANSWER: x = π/6 radians

3. tanx = √3

ANSWER: x = π/3 radians


1. Find the number of sides of a regular polygon if an exterior angle has measure π/12 radians

ANSWER: 24

[2π/(π/12) = 2(12) = 24]

2.  Evaluate 10C7 (10 combination 7)

ANSWER: 120

[ (10 x 9 x 8)/(3 x 2 x 1) = 10 x 3 x 4 = 120]

3. simplify   (tan3x + tanx)/(1 – tan3xtanx)

ANSWER: tan4x

[tan(3x + x) = tan4x]


Find each interior angle of a quadrilateral if its interior angles are represented by

1.  (x – 5)°,  (x + 20)°, (2x – 45)° and (2x – 30)֯

ANSWER: 65°, 90°, 95°, 110֯

[ 6x – 60 = 360, 6x = 420, x = 70, hence 65, 90, 95, 110]

2.  (2x – 10)֯, (x + 30)֯, (2x + 50)֯, and (x + 20)֯

ANSWER: 80°, 75°, 140°, 65°

[ 6x + 90 = 360, 6x = 270, x = 45, hence  80, 75, 140, 65]

3. (2x – 30)֯, (x + 50)֯, (x + 30)֯, (2x + 10)֯

ANSWER: 70°, 100°, 80°, 110°

[ 6x+ 60 = 360, 6x = 300, x = 50, hence 70, 100, 80, 110]


1.  Identify the polygon if in its regular form an interior angle has measure

5π/6 radians.

ANSWER: duo-decagon      [2π/n = π/6, n = 12 hence a duo-decagon]

2. Evaluate the expression  (tan87° – tan42°)/(1 + tan87°tan42°)

ANSWER: 1

[ tan(87 – 42) = tan45 = 1]

3. Find the general term Un of the linear sequence, -5, – 2, 1, 4, 7, . . .

ANSWER: Un = 3n – 8

[a = -5, d = 3, Un = a + (n – 1)d  = – 5 + 3(n – 1) = 3n – 8


Factorize completely

1. x3 + 3x2 – x – 3

ANSWER: (x – 1)(x + 1)(x + 3)

[x2(x + 3) – 1(x + 3) = (x2 – 1)(x + 3) = (x – 1)(x + 1)(x + 3)

2. x3 – 2x2 – 4x + 8

ANSWER: (x + 2)(x – 2)2

[ x2(x – 2) – 4(x – 2)= (x2 – 4)(x – 2) = (x + 2)(x – 2)2

3.  3x3 – 4x2 – 27x + 36

ANSWER:  (3x – 4)(x – 3)(x + 3)

[ 3x(x2 – 9) – 4(x2 – 9) = (3x – 4)(x2 – 9) = (3x – 4)(x – 3)(x + 3)]


Find the slope of the line passing through the given points

1. (a, b) and (3a, – 2b)

[ (-2b – b)/(3a – a) = – 3b/2a

ANSWER: -3b/2a

2. (a, b + c) and (a + c, b – c)

[(b – c – b – c)/(a + c – a) = -2c/c = -2

ANSWER: -2

3. (a, a2) and (b, b2)

[(b2 – a2)/(b – a) = (b – a)(b + a)/(b – a) = (b + a)]

ANSWER: (b + a)


1. Find a natural number n such that the number nnn3 = 2610

ANSWER: n = 2

[9n + 3n + n = 13n = 26, n = 2]

2 A fair coin is tossed three times. Find the probability of obtaining an even number of heads

ANSWER: ½

[A= {TTT, THH, HHT, HTH}, P(A) = 4/8 = ½ ]

3 Evaluate the trigonometric expression  cos33°cos27° – sin33°sin27°

ANSWER: ½

[cos(33 + 27) = cos60° = ½ ]


Find the value of x if the vectors

1.  a = 2xi + 4j and b = 8i + xj are parallel,

ANSWER: x = ± 4

[4/2x = x/8, x2 = 16, x = ± 4]

2.  a = 2xi + 4j and b = 8i + xj are perpendicular,

ANSWER: x = 0

[a.b = 16x + 4x = 0, x = 0]

3. a = 5i + xj and b = xi + 5j are parallel.

ANSWER: x = ± 5

[x/5 = 5/x, x2 = 25, x = ± 5]


Find an expression for f(x), if

1.  f(x + 1) = x2 + 5x + 7

ANSWER: f(x) = x2 + 3x + 3

[x2 + 5x + 7 = (x + 1)2 + 3x + 6 = (x + 1)2 + 3(x + 1) + 3, f(x) = x2 + 3x + 3 ]

2. f(x – 1) = x2 + x + 2

ANSWER: f(x) = x2 + 3x + 4

[ x2 + x + 2 = (x – 1)2 + 3x + 1 = (x – 1)2 + 3(x – 1) + 4, f(x) = x2 + 3x + 4]

3. f(x + 2) = x2 + 5x + 8

ANSWER: f(x) = x2 + x + 2

[ x2 + 5x + 8 = (x + 2)2 + x + 4 = (x + 2)2 + (x + 2) + 2, hence f(x) = x2 + x + 2]


1. Find the quadratic equation the sum of whose root is 10 and the product is -7

ANSWER: x2 – 10x – 7 = 0

2. Find the term without x in the expansion of (x + 1/x)8

ANSWER: 56

[8Crxr(1/x)8 – r = 8Crx2r – 8,  2r – 8 = 0, r = 4, 8C4 = (8 x 7 x 6 x 5)/(4 x 3 x 2 x 1)= 56]

3. Find the value of (tan87° + tan33°)/(1 – tan87° tan33°)

ANSWER: -√3

[tan(87 + 33) = tan120 = -tan60 = -√3]


Find the length of a side of a rhombus if the diagonals are of lengths

1.  12cm and 16cm

ANSWER: 10cm

[ 62 + 82 = x2 = 100, x = 10]

2.  10cm and 24cm

ANSWER: 13cm

[ 52 + 122 = 25 + 144 = 169 = x2, x = 13]

3.  16cm and 30cm

ANSWER: 17cm

[ 82 + 152 = 64 + 225 = 289 = x2, x = 17]


Find the binomial expansion in ascending powers of x of

1. (1 + 2x)4

ANSWER:  1 + 8x + 24×2 + 32×3 + 16×4

[1 + 4(2x) + 6(2x)2 + 4(2x)3 + (2x)4 = 1 + 8x + 24×2 + 32×3 + 16×4

2. (1 – 3x)3

ANSWER: 1 – 9x + 27×2 – 27×3

[ 1 + 3(-3x) + 3(-3x)2 + (-3x)3 = 1 – 9x + 27×2 – 27×3

3. (1 + 2x)5

ANSWER: 1 + 10x + 40×2 + 80×3 + 80×4 + 32×5

[ 1 + 5(2x) + 10(2x)2 + 10(2x)3 + 5(2x)4 + 1(2x)5]


1.  Solve for x from the equation 125x = 625

ANSWER: x = 4/3

[53x = 54, 3x = 4,x = 4/3]

2 Express the decimal number 19510 as a number in base 7.

ANSWER: 3667

(195 = 3 x 49 + 48 = 3 x 72 + 6 x 7 + 6 = 3667)


Factorize the cubic expression 

1. x3 – 27

ANSWER: (x – 3)(x2 + 3x + 9)

[ x3 – 33 = (x – 3)(x2 + 3x + 9) ]

 2. x3 + 125

ANSWER: (x + 5)(x2 – 5x + 25)

[ x3 + 53 = (x + 5)(x 2 – 5x + 25)]

 3. (x3 – 64)

ANSWER: (x – 4)(x2 + 4x + 16)

[ x3 – 43 = (x – 4)(x2 + 4x + 16)]


Solve the logarithmic equation

1. log27x = 1/3

ANSWER: x = 3

[ x = 271/3 = 3 ] 

2. log25x = 3/2

ANSWER: x = 125

[ x = 253/2 = (251/2)3 = 53 = 125]

 3. log81x = 3/4

ANSWER: x = 27

[x = 813/4 = (811/4)3 = 33 = 27]


1. Find the number of digits when the decimal number 70 is expressed as a binary number.

ANSWER: 7

[Highest power of 2 in 70 is 64 = 26, number of digits is 6 + 1 = 7]

2. The general term of a sequence is Un = 3 – 2n. Find the sum of the first 20 terms.

ANSWER: -360

[Linear sequence a = 1, d = -2, S20 = (20/2)(2(1) + 19(-2)) = 10(2 – 38) = -360]

3. Given that sinx = a/b and x is acute, find cos(π/2 – x).

ANSWER: a/b

[cos(π/2 – x) = sinx  = a/b]


1. Which of the following fractions is greater than 1/3?

A) 3/10, B) 6/17,   C) 5/18,     D) 10/33

ANSWER: B) 6/17

2. Which of the following fractions is between 1/3 and 5/14?

A) 2/3, B) ¾,   C) 29/84,   D) 3/7

ANSWER: C) 29/84

3. Which of the following fractions is less than 25%?

A) ¼, B) 2/5,    C) 3/11,     D)  5/21

ANSWER: D) 5/21


Differentiate the rational function with respect to x. 

1. y = x/(x + 1)

ANSWER: dy/dx = 1/(x + 1)2

[dy/dx = ((x + 1) – x)/(x + 1)2 = 1/(x + 1)2]

2. y = (x – 2)/(x + 2)

ANSWER: dy/dx = 4/(x + 2)2

[ dy/dx = ((x + 2) – (x – 2))/(x + 2)2 = 4/(x + 2)2

3. y = (2x – 1)/(2x + 1)

ANSWER: dy/dx = 4/(2x + 1)2

[ dy/dx = (2(2x + 1) – 2(2x – 1))/(2x + 1)2 = 4/(2x + 1)2]


1. Find the next term in the sequence  1, 27, 125, 343, . . .

ANSWER: 729

[ 13, 33 , 53, 73, . . ., next term is 93 = 81 x 9 = 729]

2.  A bicycle wheel has 18 spokes. Find the measure of angle between adjacent spokes.

ANSWER: 20°

[ 360/18 = 20]

3. Find the total surface area of a solid cube if a side has length 20 cm.

ANSWER: 2400 cm2

[ Area = 6 x 202 = 6 x 400 = 2400 cm2]


Given that i2 = -1, simplify

1. i6

ANSWER: -1

[ i6 = i4i2 = 1(-1) = -1]

2. i15

ANSWER: -i

[i15 = i12i3 = (i4)3i3 = i2i = (-1)i = -i

 3. i12

ANSWER: 1

[ i12 = i4i4i4 = 1 x 1 x 1 = 1]


Find a polynomial function f(x) of degree 3 with integer coefficients, with the given numbers as its zeros:

1.    1,  -2,  3

ANSWER: f(x) = (x – 1)(x + 2)(x – 3)

2.   2,  -3,  5

ANSWER: f(x) = (x – 2)(x + 3)(x – 5)

3.  -5,  3,  -1

ANSWER:  f(x) = (x + 5)(x – 3)(x + 1)


Solve the logarithmic equation for x

1. 2logx = log5 + log(x + 10)

ANSWER: x = 10

[ x2 = 5(x + 10), x2 – 5x – 50 = 0, (x – 10)(x + 5) = 0, x = 10]

2. logx + log(x – 3) = log18

ANSWER: x = 6

[ x(x – 3) = 18, x2 – 3x – 18 = (x – 6)(x + 3) = 0, x = 6]

3. logx + log(x + 5) = log36

ANSWER: x = 4

[ x(x + 5) = 36, x2 + 5x – 36 = 0, (x – 4)(x + 9) = 0, x = 4]


Evaluate and simplify

1. sin60° + cos60° + tan60°

ANSWER: (1 + 3√3)/2

[√3/2 + ½ + √3 = ½ (1 + 3√3) = (1 + 3√3)/2

2.  cos45° + sin45° + tan45°

ANSWER: 1 + √2

[ 1/√2 + 1/√2 + 1 = 1 + 2/√2 = 1 + √2

3.  sin30° + cos30° + tan30°

ANSWER: (3 + 5√3)/6

[1/2 + √3/2 + 1/√3 = ½ (1 + √3) + √3/3 =  ½ +  (3√3 + 2√3)/6 = (3 + 5√3)/6


1. Find the coordinates of the intercepts of the curve  x2/9 – y2/16 = 1 on the axes.

ANSWER: (3, 0), (-3, 0)

[y = 0, x2/9 = 1, x2 = 9, x = ± 3, intercepts are (3, 0) and (-3, 0,), no y-intercepts]

2. Find a natural number n such that 123n = 6610

ANSWER: n = 7

[n2 + 2n + 3 = 66, n2 + 2n = 63, n2 + 2n – 63 = 0, (n –  7)(n + 9) = 0, n = 7]

3.  Find the sum of the first 20 even natural numbers

ANSWER: 420

[S20 = (20/2)[2(2) + 2(19)] = 10(42) = 420


A fair coin and a fair die are tossed. Find the probability of obtaining

1. a Head and a number greater than 3,

ANSWER: ¼

[ A = {(H, 4), (H, 5), (H, 6)}, P(A) = 3/12 = ¼ ]

2. a Head or a Tail and a prime number,

ANSWER: 1/2

[ B = {(H,2), (T, 2), ( H, 3), (T, 3), (H,5), (T, 5)}, P(B) = 6/12 = ½ ]

3. a Tail and an odd prime or a number greater than 4.

ANSWER: ¼

[ C = {T, 3) (T, 5), (T, 6)}, P(C ) = 3/12 = ¼ ]


Find the equation of the line y = x – 3 after reflection in the

1. line  y = x

ANSWER: y = x + 3

[(x, y) →(y, x), hence x = y – 3, y = x + 3]

2.  x-axis

ANSWER: y = 3 – x

[(x, y)→(x, -y), -y = x – 3, y = 3 – x]

3.  y-axis

ANSWER: y = -x – 3

[(x, y) →(-x, y), y = -x – 3]


1. If a, b, c are the degree measures of angles in an equilateral triangle, find a relation between a, b, c.

ANSWER: a = b = c = 60֯

2. If a, b, c are the degree measures of the interior angles of a triangle, find a relation between a, b, c.

ANSWER: a + b + c = 180°

3. if a, b are the degree measures of the non-congruent angles of an isosceles trapezium, find a relation between a and b.

ANSWER: a + b = 180°


Solve for n given that nCr represents ‘n combination r’.

1.  nC2 = 10C8

ANSWER: n = 10

[n = 2 + 8 = 10]

2. 20Cn = 20C12  with n ≠ 12

ANSWER: n = 8

[ n + 12 = 20, n = 8

3  15C5 = nC10

ANSWER: n = 15

[ n = 5 + 10 = 15]


Assume x is the measure of an acute angle.

1. If sinx = 3/5, find secx

ANSWER: 5/4

[cosx = 4/5, hence secx = 5/4]

2. If tanx = 5/12 find cosecx

ANSWER: 13/5

[ sinx = 5/13, hence cosecx = 13/5]

3.  If cosx = 12/13, find cotx

ANSWER: 12/5

[ tanx = 5/12, hence cotx = 12/5]


Given f(x) = 1 – 2x and g(x) = x2 + 1, find an expression for

1. f(g(x))

ANSWER: -2x2 – 1

[ f(g(x)) = 1 – 2g(x) = 1 – 2(x2+ 1) = -2x2 – 1]

2. g(f(x))

ANSWER: (1 – 2x)2 + 1, or 4x2 – 4x + 2

[ g(f(x)) = f(x)2 + 1 = (1 – 2x)2 + 1 = 4x2 – 4x + 2]

3.  g(g(x))

ANSWER: (x2 + 1)2 + 1, or (x4 + 2x2 + 2)

[ g(g(x)) = g(x)2 + 1 = (x2 + 1)2 + 1 = x4 + 2x2 + 2]


Evaluate

1.  (13.75)2 – (3.75)2

ANSWER: 175.00

[ (13.75 + 3.75)(13.75 – 3.75) = 17.50(10.00) = 175.00

2.  (77.77)2 – (22.23)2

ANSWER: 5,554.00

[ (77.77 + 22.23)(77.77 – 22.23) = 100.00(55.54) = 5,554.00]

3.  (17.85)2 – (7.85)2

ANSWER: 257.00

[ (17.85 + 7.85)(17.85 – 7.85) = 25.70(10.00) = 257.00]


1. Solve the equation tanx = √3 in the interval 90° < x < 180°.

ANSWER: NO SOLUTION

[ in the interval 90° < x < 180°, tanx is negative]

2. Evaluate 10C4

ANSWER:210

[ 10 x 9 x 8 x 7/(4 x 3 x 2 x 1) = 210

3. Find the number of sides of a regular polygon if an interior angle measures 174°.

ANSWER: 60 sides

[ n = 360/(180 – 174) = 360/6 = 60]


Find the number of sides of a regular polygon if an interior angle has measure

1.  171°

ANSWER: 40

[ n = 360/9 = 40]

2.  177°

ANSWER: 120

[ n = 360/3 = 120]

3. 160°

ANSWER: 18

[ n = 360/20 = 18]


If f(x) = 2x – 1, g(x) = x + 2 and h(x) = x2, evaluate

1. f(g(h(2)))

ANSWER: 11

[ h(2) = 4, g(4) = 4 + 2 = 6, f(6) = 12 – 1 = 11]

2.  g(f(h(-1)))

ANSWER: 3

[ h(-1) = 1, f(1) = 1, g(1) = 1 + 2 = 3]

3. h(f(g(-2)))

ANSWER: 1

[ g(-2) = -2 + 2 = 0, , f(0) = 0 – 1 = -1, h(-1) = 1]


1. Solve the quadratic equation 4x2 + x – 5 = 0

ANSWER: x = 1, -5/4

[4x2 + 5x – 4x – 5 = 0, x(4x + 5) – 1(4x + 5) = (x – 1)(4x + 5) = 0, x = 1, -5/4]

2. Find the first term a and the common difference d, of a linear sequence given third term is 7 and seventh term is 15.

ANSWER: a = 3, d = 2

[a + 2d = 7, a + 6d = 15, 4d = 8, d = 2 and a = 7 – 4 = 3]


Find the coordinates of the image of the point A(3, 5) after reflection 

1. in the origin,

ANSWER: (-3, -5)

2. in the line y = 3,

ANSWER: (3, 1)

3. in the line x = 2,

ANSWER: (1, 5)


Find dy/dx if

1. x2 + xy – y2 = 9

ANSWER: dy/dx = (2x + y)/(2y – x)

[2x + y + xdy/dx  -2ydy/dx = 0, dy/dx(2y – x) = (2x + y), dy/dx = (2x + y)/(2y – x)]

2.  2x2 – xy + y2 = 6

ANSWER: dy/dx = (4x – y)/(x – 2y)

[ 4x – y – xdy/dx + 2ydy/dx = 0, dy/dx(x – 2y) = (4x – y), dy/dx = (4x – y)/(x – 2y)]

3. x2 + xy – 3y2 = 10

ANSWER: dy/dx = (2x + y)/(6y – x)

[2x + y + xdy/dx – 6ydy/dx = 0, dy/dx(6y – x) = (2x + y), dy/dx = (2x + y)/(6y – x)]


1. Find n if   123n = 3810

ANSWER: n = 5

[ n2 + 2n + 3 = 38, n2 + 2n – 35 = 0, (n + 7)(n – 5) = 0, n = 5]

2. Find the greatest value of the expression 3sinx + 4cosx

ANSWER: 5

[R = √(32 + 42) =√25 = 5]

3. Rationalize the denominator 3/(√5 – √2)

ANSWER: √5 + √2

[3(√5 + √2)/(5 – 2) = √5 + √2]


Find the coordinates of the vertex of the quadratic curve given by

1. y = x2 + 6x + 10

ANSWER:  (-3, 1)

[ x2 + 6x + 9 + 1 = (x + 3)2 + 1, hence vertex is (-3, 1)]

2. y = x2 – 8x + 12

ANSWER: (4, – 4)

[ x2 – 8x + 16 – 4 = (x – 4)2 – 4, hence (4, -4)]

3. y = x2 + 6x – 1

ANSWER: (-3, -10)

[ x2 + 6x + 9 – 10 = (x + 3)2 – 10, hence (-3, -10)]


Evaluate the trigonometric expression

1. sin17°cos13° + sin13°cos17°

ANSWER: ½ or 0.5

[ sin(17 + 13) = sin30° = ½ ]

2. sin25֯sin35֯ – cos25֯cos35֯

ANSWER: -1/2 or -0.5

[ -(cos25cos35 – sin25sin35) = – cos(25 + 35) = -cos60 = – ½]

3.  (tan32° + tan28°)/(1 – tan32°tan28°)

ANSWER: √3

[ tan(32° + 28°) = tan60° = √3]


1. Find the prime numbers between 80 and 90

ANSWER: 83, 89

[ 81, 82, (83), 84, 85, 86, 87, 88,  (89)]

2. Find the equation of the image of the line y = 2x after reflection in the y-axis.

ANSWER: y = -2x

[(x, y)→(-x, y), y = 2(-x) = -2x]

3. A fair die is thrown. Find the probability of getting a multiple of 2 or a multiple of 3.

ANSWER: 2/3

[ A = {2, 3, 4, 6}, P(A) = 4/6 = 2/3]


Determine the nature of the roots of the given equation without solving.

1. x2 + 5x + 7 = 0

ANSWER: NO REAL ROOTS

[ b2 – 4ac = 25 – 28 = -3 < 0, hence no real roots]

2.  x2 – 2x – 3 = 0

ANSWER: 2 REAL RATIONAL ROOTS

[ b2 – 4ac = 4 + 12 = 16, hence 2 real rational roots]

3. x2 + 5x – 7 = 0

ANSWER: 2 REAL IRRATIONAL ROOTS

[ b2 – 4ac = 25 + 28 = 53 > 0, hence 2 real irrational roots]


Find the distance between the pair of points  

1. A(2, 4) and B(6, 7)

ANSWER: 5

[d2 = 32 + 42 = 25, d = 5] 

2. C(-2, -3) and D(2, 3)

ANSWER: 2√13

[d2 = 42 + 62 = 16 + 36 = 52 = 4(13), d = 2√13]

3. E(3, -1) and F(-2, 6)

ANSWER: √74

[ d2 = 52 + 72 = 25 + 49 = 74, d = √74]


1. Multiply and simplify  (x – 3)(x2 + 3x + 9)

ANSWER: x3 – 27   (difference of two cubes)

2. Find an equation of a line having x- intercept of 4 and a y-intercept of -4.

ANSWER:  x – y = 4

[ x/4 + y/-4 = 1, x – y = 4]

3. If i2 = -1, evaluate (5 – 3i)(5 + 3i)

ANSWER: 34

[ 25 – 9i2 = 25 + 9 = 34]


Find the quadratic equation whose roots are

1.  3 ± √5

ANSWER: x2 – 6x + 4 = 0

[sum of roots = 6, product = 9 – 5 = 4, hence x2 – 6x + 4 = 0]

2.  5 ± √7

ANSWER: x2 – 10x + 18 = 0

[ sum of roots = 10, product =25 – 7 = 18, hence x2 – 10x + 18 = 0]

3.  -4 ± 3√2

ANSWER:  x2 + 8x – 2 = 0

[ sum of roots = -8, product = 16 – 18 = -2, hence x2 + 8x – 2 = 0]


1.  Express a relation between x and y if  x and y are degree measures of adjacent angles of a parallelogram.

ANSWER: x + y = 180     (Accept x + y = 180°)

2. Two fair coins are tossed once. Find the probability of obtaining an even number of heads.

ANSWER: ½           [A = {HH, TT}, P(A) = 2/4 = ½]

3. Differentiate the function   y = (2x3 – 3x2)4

ANSWER:  dy/dx = 24(x2 – x)(2x3 – 3x2)3

[dy/dx = 4(6x2 – 6x)(2x3 – 3x2)3 = 24(x2 – x)(2x3 – 3x2)3]


Suppose for some function f(x + 2) = 2x + 3. Evaluate  

1. f(-2)

ANSWER: -5

[x + 2 = -2, x = – 4, f(-2) = 2(-4) + 3 = -5] 

2. f(2)

ANSWER: 3

[ x + 2 = 2, x = 0, f(2) = 2(0) + 3 = 3]

3. f(5)

ANSWER: 9

[ x + 2 = 5, x = 3, f(5) = 2(3) + 3 = 9],


Rationalize the denominator

1. 3/(√5 – √2)

ANSWER: √5 + √2

[ 3(√5 + √2)/(5 – 2) = √5 + √2

2. 5/(√15 + √10)

ANSWER: √15 – √10

[ 5(√15 – √10)/(15 – 10) = √15 – √10]

3.  6/(√13 – √7)

ANSWER: √13 + √7

[6(√13 + √7)/(13 – 7) = √13 + √7


1. Solve the equation sinx = √3/2 in the interval 90° < x < 180°

ANSWER: x = 120°

2. Find the coordinates of the image of the point A(2, -3) after reflection in the      x-axis.

ANSWER: (2, 3)

3. For what values of k will the equation kx2 + 4x – k = 0 have real roots?

ANSWER: All real values of k

[ 16 + 4k2 > 0, hence all real values of k]


Find the greatest value of

1. (sec2x – tan2x)

ANSWER: 1

[ sec2x = tan2x + 1, hence sec2x – tan2x = 1]

2.  (sinxcos30° + cosxsin30°)

ANSWER: 1

[ sin(x + 30), greatest value = 1]

3.  2sinxcosx + 5

ANSWER: 6

[ sin2x + 5, greatest value is 1 + 5 = 6]


Differentiate the given function with respect to x.

1. y = (2x + 1)6

ANSWER: dy/dx = 12(2x + 1)5

2. y = (3 – 2x)-6

ANSWER: dy/dx = 12(3 – 2x)-7

[ dy/dx = -6(-2)(3 – 2x)-7 = 12(3 – 2x)-7]

3.  y = (x2 – 2x)8

ANSWER: dy/dx = 16(x – 1)(x2 – 2x)7

[ dy/dx = 8(2x – 2)(x2 – 2x)7 = 16(x – 1)(x2 – 2x)7  Use chain rule]


1. If A is acute and cosA = 12/13, find tanA

ANSWER: 5/12

[sinA = 5/13, tanA = sinA/cosA = (5/13)/(12/13) = 5/12]

2. Solve the exponential equation 62x – 1 = 216

ANSWER: x = 2

[ 216 = 63, 2x – 1 = 3, x = 2]

3.  Find the coefficient of x3 in the expansion of (1 + 2x)6

ANSWER: 160

[ 6C3(2x)3, 20(23) = 160]


Express the variation as an equation

1. y varies partly as x and partly as the inverse of x2

ANSWER: y = ax + b/x2   (a and b are constants)

2. y is partly a constant and partly varies as x3

ANSWER: y = a + bx3

3. y varies jointly as x and z2 and inversely as √w.

ANSWER: y = kxz2/√w


Factorise as an exact cube.

1. x3 – 6x2 + 12x – 8

ANSWER: (x – 2)3

[ x3 – 3(x)2(-2) + 3(x)(-2)2 + (-2)3 = (x – 2)3]

2.  x3 + 9x2 + 27x + 27

ANSWER: (x + 3)3

[ x3 + 3x2(3) + 3(x)(3)2 + 33 = (x + 3)3]

3.  x3 + 12x2 + 48x + 64

ANSWER: ( x + 4)3

[ x3 + 3(x)24 + 3(x)(4)2 + 43 = (x + 4)3]


1. Find x if the vectors  a = xi – 3j and b = 5i + 10j are perpendicular.

ANSWER: x = 6

[ a.b = 5x – 30 = 0, x = 6]

2. Find the stationary point of the function y = (x – 2)2 + 1 and state whether a maximum or a minimum.

ANSWER: (2, 1) minimum

3.  Simplify  (1 + √3)/(1 – √3)

ANSWER: -(2 + √3)

[(1 + √3)2/(1 – 3) = (4 + 2√3)/-2 = -2 – √3 = -(2 + √3)


Given the relation R = {(1, 2), (2, -3), (3, 5), (4, 7)}

1. find the domain of the relation,

ANSWER: {1, 2, 3, 4}

2. find the range of the relation,

ANSWER: {2, -3, 5, 7}

3. determine if R is a function.

ANSWER: R is a function


Suppose for some function f, f(x – 1) = 5x. Evaluate

1. f(2)

ANSWER: 15

[x – 1 = 2, x = 3, f(2) = 5(3) = 15]

2. f(-2)

ANSWER: -5

[ x – 1 = -2, x = -1, f(-2) = 5(-1) = -5]

3. f(-5)

ANSWER: -20

[ x – 1 = -5, x = -4, f(-5) = 5(-4) = -20]


1. Find the midpoint of the line segment connecting the points A(1/2, 1/3) and B(1/3, ½)

ANSWER: (5/12, 5/12)

[(1/2 + 1/3)/2, (1/3 + ½)/2) = ((5/6)/2, (5/6)/2) = (5/12, 5/12)

2. Solve the linear equation 2(7x – 4) – 4(2x – 6) = 3x + 31

ANSWER: x = 5

[14x – 8x – 8 + 24 = 3x + 31, 3x = 39 – 24 = 15, x = 5]

3. Multiply and simplify (x + 2)(x2 – 2x + 4)

ANSWER: (x3 + 8)

[sum of two cubes formula]


Simplify the trigonometric expression

1. (tanx + tan3x)/(1 – tanxtan3x)

ANSWER: tan4x

[ tan(x + 3x) = tan4x]

2.  (tan5x – tan2x)/(1 + tan5xtan2x)

ANSWER: tan3x

[ tan(5x – 2x) = tan3x]

3.  (1 – tan2x)/(2tanx)

ANSWER: cot2x or 1/tan2x

[ 1/tan(x + x) = 1/tan(2x) = cot2x]


Find the sum of the interior angles of the given polygon in radians

1. duo-decagon

ANSWER: 10π radians

[ (12 – 2)π = 10π]

2. nonagon

ANSWER: 7π radians

[ (9 – 2)π = 7π]

3.  icosagon

ANSWER:18π radians

[ (20 – 2)π = 18π]


1. Find the value of x if  (x – 2), (2x + 2), (x + 12) are consecutive terms of a linear sequence.

ANSWER: x = 3

[ 2(2x + 2) = x – 2 + x + 12 = 2x + 10, 2x = 10 – 4 = 6, x = 3]

2. Find the coordinates of the image of the point P(2, 5) after reflection in the line y = 6.

ANSWER: (2, 7)

[5 + 1 + 1 = 7, hence (2, 7)

3. Find the term without x in the expansion of (x2 + 1/x)9

ANSWER: 84

[ 9Crx2r(1/x)9 – r, x2r + r – 9, 3r – 9 = 0, r = 3, 9C3 = 9 x 8 x 7 /3 x 2 x 1 = 84]


 

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